WebSolve for ? tan (theta)=-1 tan (θ) = −1 tan ( θ) = - 1 Take the inverse tangent of both sides of the equation to extract θ θ from inside the tangent. θ = arctan(−1) θ = arctan ( - 1) Simplify the right side. Tap for more steps... θ = − π 4 θ = - π 4 The tangent function is negative in the second and fourth quadrants.

How to solve this (tan^2 theta = tan theta) - Quora

WebFeb 5, 2024 · Explanation: First,Solve for tan(θ) By using the fact That tan(θ) = sin(θ) cos(θ) and Since You said that sin(θ) = 0.5 = 1 2 and cos(θ) = − √3 2 That means tan(θ) = sin(θ) cos(θ) = 1 2 − √3 2 = − 1 √3 = − √3 3 Lets Use the cos(θ) equation to find θ θ = cos−1( − √6 2) = ilog(u) when u = √6 + √2 2 = (√2) 1 +√3 2 Answer link Aviv S. Feb 5, 2024 WebMay 18, 2015 · 2 Approach by your substitution: u = tan θ, d u = sec 2 θ d θ ∫ tan θ sec 4 θ d θ = ∫ u sec 2 θ d u = ∫ u ( 1 + u 2) d u = ∫ u + u 3 d u = 1 2 u 2 + 1 4 u 4 + C = 1 2 tan 2 θ + 1 4 tan 4 θ + C Wolfram Alpha's Approach: u = sec θ, d u = sec θ tan θ d θ ∫ sec 4 θ tan θ d θ = ∫ u 3 d u = 1 4 u 4 + c = 1 4 sec 4 θ + C 0 Share Cite Follow earn free vbucks codes

trigonometry - Prove $1 + \tan^2\theta = \sec^2\theta

WebJun 1, 2024 · Write the double-angle formula for tangent. tan(2θ) = 2 tan θ 1 − tan2θ In this formula, we need the tangent, which we were given as tan θ = − 3 4 . Substitute this value into the equation, and simplify. tan(2θ) = 2( − 3 4) 1 − ( − 3 4)2 = − 3 2 1 − 9 16 = − 3 2(16 7) = − 24 7 Exercise 9.3.1 Given sin α = 5 8 ,with θ in quadrant I, find cos(2α) . WebIdentify all exact solutions to the equation [latex]2\left(\tan x+3\right)=5+\tan x,0\le x<2\pi [/latex]. Show Solution ... Solve [latex]{\sin }^{2}\theta =2\cos \theta +2,0\le \theta \le 2\pi[/latex]. [Hint: Make a substitution to express the equation only in terms of cosine.] WebTrigonometry Solve for ? tan (2theta)=-1 tan (2θ) = −1 tan ( 2 θ) = - 1 Take the inverse tangent of both sides of the equation to extract θ θ from inside the tangent. 2θ = … cswb ontario