WebAt STP of 273.15 K (0°C) and 1 atm, the molar volume (Vm) of a gas is 22.4 L/mol. Convert 112 L O2 to moles (n) O2. n = V/Vm n O2 = 112 L O2/22.4 L/mol = 5.00 mol O2 Balanced equation: 2NO + O2 → 2NO2 Multiply 5.00 mol O2 by the mole ratio between NO and O2 from the balanced equation, so that mol O2 cancel, leaving mol NO. Web26 feb. 2016 · Clearly, this is a finite number of dioxygen molecules. This same finite number (which is N A × 10.0 ⋅ g 32.0 ⋅ g ⋅ mol−1, N A = Avogadro's number) is the same mass whatever the state, solid, liquid, or gas. Of course, at STP, dioxygen is a gas, but 10.0 g …

What is the volume of 2.0 moles of an ideal gas at STP?

Web6 okt. 2024 · Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as: = 63.04 g ≈ … WebHow many grams of NO 2 gas would it take to exert a pressure of 2.5 atm in a 3.00 L container at a temperature of 45 o C? What mass of hydrogen gas would occupy a … earthjoy village

SCH 3U Workbook Answer Key - Unit 4 by Michael Papadimitriou

Web4 aug. 2024 · We start by determining the number of moles of gas present. We know that 22.4 liters of a gas at STP equals one mole, so: 867 L × 1 mol 22.4 L = 38.7 mol We also know the molecular weight of N 2 ( 28.0 g/mol), so we can then calculate the weight of nitrogen gas in 867 liters: 38.7 mol × 28 g 1 mol = 1083.6 g N 2 Step 3: Think about your … Web11 aug. 2010 · Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of... WebFor the combustion reaction 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), how many liters of O2(g) would react with 500 L of NH3 at STP? (8.000x10^-1) g of a gas is collected in the … earthjoy tree climbing